## What is the sum of the cubes of the first natural numbers

Sum of cubes of the first 4 natural numbers = 1^{3} + 2^{3} + 3^{3} + 4^{3} = 1 + 8 + 27 + 64 = **100**.

## How do you find the sum of the cube of the first n natural numbers

**Solution:**

- We know the sum of the cubes of first n natural numbers (S) = {n(n+1)2}2.
- Therefore, the sum of the cubes of first 12 natural numbers = {12(12+1)2}2.
- We know the sum of the cubes of first n natural numbers (S) = {n(n+1)2}2.
- Therefore, the sum of the cubes of first 25 natural numbers = {25(25+1)2}2.

## What is the formula of sum of cubes

It is represented by a^{3} + b^{3} and is read as a cube plus b cube. The sum of cubes (a^{3} + b^{3}) formula is expressed as **a ^{3} + b^{3} = (a + b) (a^{2} – ab + b^{2})**.

## What is sum of natural numbers

The formula of the sum of first n natural numbers is **S=n(n+1)2** .

## What is the formula for sum of squares of first n natural numbers

Sum of Squares of Natural Numbers Proof

The sum of n natural numbers is represented as **[n(n+1)]/2**. If we need to calculate the sum of squares of n consecutive natural numbers, the formula is Σn^{2} = [n(n+1)(2n+1)] / 6. It is easy to apply the formula when the value of n is known.

## What is the sum of squares of first 10 natural numbers

The sum of the squares of the first ten natural numbers is, **12 + 22 + ** **+ 102 = 385** The square of the sum of the first ten natural numbers is, (1 + 2 + + 10)2 = 552 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

## What is the sum of n numbers

**S _{n} = n(n+1)/2**

Hence, this is the formula to calculate sum of 'n' natural numbers.

## How many terms of the Series 1 Cube 2 Cube 3 cube should be taken to get the sum 1296

**It is the real solution of the equation x ^{3} = 1296. The cube root of 1296 is expressed as ∛1296 or 6 ∛6 in the radical form and as (1296)^{⅓} or (1296)^{0}^{.}^{33} in the exponent form.**

Cube Root of 1296.

1. | What is the Cube Root of 1296? |
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4. | FAQs on Cube Root of 1296 |

## What is the sum of n odd numbers

The sum of n odd numbers formula is described as follows, Sum of n odd numbers = **n ^{2}** where n is a natural number and represents the number of terms.

## What is the sum of the cubes of the first 7 natural numbers

Right Answer is: **A**

**= 784**.

## What is the formula for sum of cubes

It is represented by a^{3} + b^{3} and is read as a cube plus b cube. The sum of cubes (a^{3} + b^{3}) formula is expressed as **a ^{3} + b^{3} = (a + b) (a^{2} – ab + b^{2})**.

## What is the sum of first natural numbers

Here **a = 1, d = 1**. Hence option (4) is the answer. Was this answer helpful?

## Is sum of all natural numbers equals 1 12

For those of you who are unfamiliar with this series, which has come to be known as the Ramanujan Summation after a famous Indian mathematician named Srinivasa Ramanujan, it states that **if you add all the natural numbers, that is 1, 2, 3, 4, and so on, all the way to infinity, you will find that it is equal to -1/12**.

## What is the sum of natural numbers from 1 to 100

Natural numbers from 1 to 100

∴ The sum of all natural number from 1 to 100 is **5050**.

## What is the sum of 1 to n

Sum of the First n Natural Numbers. We prove the formula 1+ 2+ + n = **n(n+1) / 2**, for n a natural number.Feb 13, 2001

## What is the sum of first 10 natural numbers

Therefore, the sum of the first 10 natural numbers is **55**.

## What is the sum of first 45 natural numbers

S = n(n+1)/2 = 45(45+1)/2 =45*23=**1035**.

## What is the sum of all numbers called

**A summation, also called a sum**, is the result of arithmetically adding numbers or quantities. A summation always contains a whole number of terms.